Date: 25 January 1948
Month |
Jan |
Feb |
Mar |
Apr |
May |
Jun |
Jul |
Aug |
Sep |
Oct |
Nov |
Dec |
Code |
0 |
3 |
3 |
6 |
1 |
4 |
6 |
2 |
5 |
0 |
3 |
5 |
Steps to find the day of the week:
Last two digit of the year and Year code (1900), so no addition of odd days for year. |
48 |
No. of the leap year (quotient) |
48 ÷ 4 Divisor = 12 |
Code of the month |
0 |
Date |
25 |
Total = (48+ 12 + 0 + 25) = 85
And 85 ÷ 7, we get 1 as the remainder.
Code |
Day |
1 |
Sunday |
2 |
Monday |
3 |
Tuesday |
4 |
Wednesday |
5 |
Thursday |
6 |
Friday |
0 |
Saturday |
‘1’ is the code for Sunday.
Hence, 'Sunday’ is the correct answer.
Key Points